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A flashlight has \( 10 \) batteries out of which \( 4 \) are dead. If \( 3 \) batteries are selected without
replacement andtested, then the probability that all \( 3 \) are dead is
Options:
replacement andtested, then the probability that all \( 3 \) are dead is
Solution:
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Verified Answer
The correct answer is:
\( \frac{1}{30} \)
Total number of batteries are 10
Number of dead batteries is 4
So, P(all three dead)
$=\frac{4}{10} \times \frac{3}{9} \times \frac{2}{8}=\frac{1}{30}$
Number of dead batteries is 4
So, P(all three dead)
$=\frac{4}{10} \times \frac{3}{9} \times \frac{2}{8}=\frac{1}{30}$
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