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A fluid is in streamline flow across a horizontal pipe of variable area of cross-section. For this which of the following statements is correct?
Options:
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Verified Answer
The correct answer is:
Both (a) and (b)
According to the equation of continuity,
$$
A v=\text { constant }
$$
Therefore, velocity of the fluid is minimum at the widest part and maximum at the narrowest part of the horizontal pipe.
Again, according to Bernoulli's principle for horizontal pipe,
$$
p+\frac{1}{2} p v^{2}=\text { constant }
$$
Hence, $p$ is more, $v$ is less and vice-versa.
Therefore, when a fluid is flowing through the horizontal pipe of variable area of cross-section, then velocity is maximum at the narrowest part of the pipe and pressure is maximum at the widest part of the pipe.
$$
A v=\text { constant }
$$
Therefore, velocity of the fluid is minimum at the widest part and maximum at the narrowest part of the horizontal pipe.
Again, according to Bernoulli's principle for horizontal pipe,
$$
p+\frac{1}{2} p v^{2}=\text { constant }
$$
Hence, $p$ is more, $v$ is less and vice-versa.
Therefore, when a fluid is flowing through the horizontal pipe of variable area of cross-section, then velocity is maximum at the narrowest part of the pipe and pressure is maximum at the widest part of the pipe.
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