Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A fluid of density ' $\rho$ ' is flowing through a uniform tube of diameter ' $\mathrm{d}$ '. The coefficient of viscosity of the fluid is ' $\eta$ ', then critical velocity of the fluid is
PhysicsMechanical Properties of FluidsMHT CETMHT CET 2023 (11 May Shift 2)
Options:
  • A inversely proportional to ' $\eta$ '
  • B directly proportional to ' $\eta$ '
  • C directly proportional to 'd'
  • D directly proportional to ' $\rho$ '
Solution:
2127 Upvotes Verified Answer
The correct answer is: directly proportional to ' $\eta$ '
The equation for critical velocity is given as:
$\mathrm{v}=\mathrm{k} \frac{\eta}{\rho \mathrm{r}}$
$\therefore \quad$ The critical velocity is directly proportional to $\eta$.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.