A force F = 75 N is applied on a block of mass 5 kg along the fixed smooth incline as shown in the figure. Here gravitational acceleration g = 10 m s -2 . The acceleration of the block is

Question

A force F = 75 N is applied on a block of mass 5 kg along the fixed smooth incline as shown in the figure. Here gravitational acceleration g = 10 m s -2 . The acceleration of the block is, 10 m s - 2 downwards the incline, 10 m s - 2 upwards the incline, 5 m s - 2 downwards the incline, 5 m s - 2 upwards the incline

MARKS App · Accepted Answer

Consider the force acting on the block as shown below Given, F = 75 N m = 5 kg Acceleration of the block F - m g sin ⁡ 30 o = m a ⇒ a = F - m g sin ⁡ 30 o m ⇒ a = 75 - 5 g sin ⁡ 30 o 5 a = 50 5 = 10 m s -2 upwards the inclined plane

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