Search any question & find its solution
Question:
Answered & Verified by Expert
A force $F$ acting on an object varies with distance $x$ as shown in the figure. The force is in $\mathrm{N}$ and $x$ in $\mathrm{m}$. The work done by the force in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is
Options:
Solution:
2918 Upvotes
Verified Answer
The correct answer is:
$13.5 \mathrm{~J}$
Work done by force $=$ Area under force- displacement graph.
$=3 \times 3+\frac{1}{2} \times 3 \times 3=9+4.5=13.5 \mathrm{~J}$
$=3 \times 3+\frac{1}{2} \times 3 \times 3=9+4.5=13.5 \mathrm{~J}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.