A force F is applied on a block of mass 3 kg which rests on a horizontal surface with a coefficient of friction 1 2 3 . The maximum value of F for which the block doesn't move, is [Take g = 10 m s - 2 ]

Question

A force F is applied on a block of mass 3 kg which rests on a horizontal surface with a coefficient of friction 1 2 3 . The maximum value of F for which the block doesn't move, is [Take g = 10 m s - 2 ], 20 N, 10 N, 15 N, 25 N

MARKS App · Accepted Answer

From acting on block are shown in adjoining figure As the block does not move, hence F cos ⁡ 60 ° = f = μ N = μ M g + F sin ⁡ 60 ° ∴ F 1 2 = 1 2 3 3 × 10 + F ⋅ 3 2 On simplification, we get F = 20 N

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