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Question: Answered & Verified by Expert
A force F = - K y i ^ + x j ^ (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to the (a,a). The total work done by the force F on the particle is
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Options:
  • A -2Ka2
  • B 2Ka2
  • C -Ka2
  • D Ka2
Solution:
2124 Upvotes Verified Answer
The correct answer is: -Ka2
F=-Kyi^+xj^

On moving from origin to (a, 0).

Work done=0a-Kyi^+xj^.dx

= 0

as y = 0

Work done from (a, 0) to (a, 0)

Work done  w=0a-Kyi^+xj^dy  but x = a

= 0 a - K a dy

= - Ka 2

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