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A force of $5 \mathrm{~N}$ acts on a particle along a direction making an angle of $60^{\circ}$ with vertical. Its vertical component be
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The correct answer is:
$2.5 \mathrm{~N}$
The component of force in vertical direction
$=F \cos \theta=F \cos 60^{\circ}=5 \times \frac{1}{2}=2.5 \mathrm{~N}$
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