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Question: Answered & Verified by Expert
A function f: ZZ is defined as fn=n+1nodd integern2neven integer. If kodd integer and fffk=33, then the sum of the digits of k is
MathematicsFunctionsJEE Main
Options:
  • A 7
  • B 5
  • C 9
  • D 8
Solution:
2184 Upvotes Verified Answer
The correct answer is: 5
 kodd integer

fk=k+1 which is even

ffk=k+12

If k+12 is odd 33=k+12+1k=63 not possible (because k+12 is even)

If k+12 is even 33=k+12233=k+14k=131

Sum of digits =5

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