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A galvanometer coil has a resistance of $12 \Omega$ and the metre show full scale deflection for a current of $3 \mathrm{~m}$ A. How will you convert the metre into a voltmeter of range 0 to $18 \mathrm{~V}$ ?
Solution:
2334 Upvotes
Verified Answer
By using the formula
$R_V=\frac{V}{I_g}-G$
We can calculate required resistance to be connected in series.
$$
R_V=\frac{18}{3 \times 10^{-3}}-12=5,988 \Omega
$$
$R_V=\frac{V}{I_g}-G$
We can calculate required resistance to be connected in series.
$$
R_V=\frac{18}{3 \times 10^{-3}}-12=5,988 \Omega
$$
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