Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A galvanometer coil has a resistance of \( 50 \Omega \) and the meter shows full scale deflection for a
current of \( 5 \mathrm{~mA} \), This galvanometer is converted into voltmeter of range \( 0-20 \mathrm{~V} \) by connecting
PhysicsCurrent ElectricityKCETKCET 2016
Options:
  • A \( 3950 \Omega \) in series with galvanometer
  • B \( 4050 \Omega \) in series with galvanometer
  • C \( 3950 \Omega \) in parallel with galvanometer
  • D \( 4050 \Omega \) in parallel with galvanometer
Solution:
1227 Upvotes Verified Answer
The correct answer is: \( 3950 \Omega \) in series with galvanometer
We know, \( R=\frac{V}{I_{g}}-G \)
Given,
\[
\begin{array}{l}
V=20 \mathrm{~V} ; I_{g}=5 \mathrm{~mA}=5 \times 10^{-3} \mathrm{~A} ; G=50 \Omega \\
\Rightarrow R=\frac{20}{5 \times 10^{-3}}-50=\frac{20}{0.005}-50=3950 \Omega
\end{array}
\]
Therefore, the given galvanometer is converted into voltmeter of range \( 0-20 \mathrm{~V} \) by connecting \( 3950 \Omega \) in series with
galvanometer.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.