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A galvanometer having a coil resistance of $60 \Omega$ shows full scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents upto $5.0 \mathrm{amp}$ by :
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The correct answer is:
Putting in parallel a resistance of $15 \Omega$
$$
\begin{aligned}
\mathrm{Ig} & =1.0 \mathrm{~A}, \mathrm{G}=60 \mathrm{q}, \mathrm{I}=5.0 \mathrm{~A} \\
\mathrm{~S} & =\frac{\mathrm{I}_{\mathrm{g}}}{\mathrm{I}-\mathrm{I}_{\mathrm{g}}} \mathrm{G} \\
\mathrm{G} & =\frac{1.0}{5.0-1.0}=60 \\
& =15 \Omega \text { in parallel }
\end{aligned}
$$
\begin{aligned}
\mathrm{Ig} & =1.0 \mathrm{~A}, \mathrm{G}=60 \mathrm{q}, \mathrm{I}=5.0 \mathrm{~A} \\
\mathrm{~S} & =\frac{\mathrm{I}_{\mathrm{g}}}{\mathrm{I}-\mathrm{I}_{\mathrm{g}}} \mathrm{G} \\
\mathrm{G} & =\frac{1.0}{5.0-1.0}=60 \\
& =15 \Omega \text { in parallel }
\end{aligned}
$$
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