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A galvanometer having internal resistance $10 \Omega$ requires 0.01 A for a full scale deflection. To convert this galvanometer to a voltmeter of full-scale deflection at $120 \mathrm{V}$, we need to connect a resistance of
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The correct answer is:
$11990 \Omega$ in series
Resistance $R=\frac{V}{i_{g}}-G=\frac{120}{0.01}-10$
$$
\begin{aligned}
&=12000-10 \\
R=11990 \Omega
\end{aligned}
$$
To convert a galvanometer into a voltmeter, high resistance should connect in series.
$$
\begin{aligned}
&=12000-10 \\
R=11990 \Omega
\end{aligned}
$$
To convert a galvanometer into a voltmeter, high resistance should connect in series.
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