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A galvanometer of resistance $100 \Omega$ gives full-scale defection for $10 \mathrm{~mA}$ current. What should be the value of the shunt so that it can measure a current of $100 \mathrm{~mA}$ ?
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Verified Answer
The correct answer is:
$11.11 \Omega$
Given,
Resistance of a galvanometer, $G=100 \Omega$,
Current at full-scale deflection, $\mathrm{i}_{\mathrm{g}}=10 \mathrm{~mA}$
Measured current, $\mathrm{i}=100 \mathrm{~mA}$
The value of the shunt is calculated as, $\frac{R}{Q}=\frac{i_3}{i-i_g}$
$\begin{aligned}
& \Rightarrow R=\frac{G_y}{i-i_y} \\
& R=\frac{100 \times 10 \times 10^{-3}}{(100-10) \times 10^{-3}}=11.11 \Omega
\end{aligned}$
Resistance of a galvanometer, $G=100 \Omega$,
Current at full-scale deflection, $\mathrm{i}_{\mathrm{g}}=10 \mathrm{~mA}$
Measured current, $\mathrm{i}=100 \mathrm{~mA}$
The value of the shunt is calculated as, $\frac{R}{Q}=\frac{i_3}{i-i_g}$
$\begin{aligned}
& \Rightarrow R=\frac{G_y}{i-i_y} \\
& R=\frac{100 \times 10 \times 10^{-3}}{(100-10) \times 10^{-3}}=11.11 \Omega
\end{aligned}$
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