A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series shows full-scale deflection of 30 divisions. The additional series resistance required to reduce the deﬂection to 20 divisions is

Question

A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series shows full-scale deflection of 30 divisions. The additional series resistance required to reduce the deﬂection to 20 divisions is, 2950 Ω, 1500 Ω, 4440 Ω, 7400 Ω

MARKS App · Accepted Answer

Current flowing in galvanometer, I = 3 50 + 2950 I = 10 - 3 A Current for 30 division = 10 - 3 A Current for 20 division = 10 - 3 30 × 20 = 2 3 × 10 - 3 A Let the additional series resistance = R ∴ 2 3 × 10 - 3 = 3 50 +2950+ R R= 1500 Ω

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