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A gas absorbs a photon of $355 \mathrm{~nm}$ and emits at two wavelengths. If one of the emissions is at $680 \mathrm{~nm}$, the other is at:
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The correct answer is:
$743 \mathrm{~nm}$
$743 \mathrm{~nm}$
$\frac{1}{\lambda_{\text {absorted }}}=\frac{1}{\lambda_1}+\frac{1}{\lambda_2}$
$\Rightarrow \frac{1}{355}=\frac{1}{680}+\frac{1}{\lambda_2}$
$\Rightarrow \lambda_2=742.8 \cong 743 \mathrm{~nm}$
$\Rightarrow \frac{1}{355}=\frac{1}{680}+\frac{1}{\lambda_2}$
$\Rightarrow \lambda_2=742.8 \cong 743 \mathrm{~nm}$
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