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A gas formed by the action of alcoholic $\mathrm{KOH}$ on ethyl iodide, decolourises alkaline $\mathrm{KMnO}_{4}$. The gas is
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$\mathrm{C}_{2} \mathrm{H}_{4}$
By the action of alc. $\mathrm{KOH}$ on ethyl iodide, ethylene gas is formed by elimination reaction. Ethylene decolourises alkaline $\mathrm{KMnO}_{4}$.
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