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Question: Answered & Verified by Expert
A gas is allowed to expand at constant temperature from a volume of 1.0 L to 10.1 L against an external pressure of 0.50 atm. If the gas absorbs 250 J of heat from the surroundings, what are the values of q, w and ΔE? (Given 1 L atm = 101.0 J)
ChemistryThermodynamics (C)JEE Main
Options:
  • A
    q w ΔE
    250 J - 460 J - 210 J
  • B
    q w ΔE
    -250 J - 460 J - 710 J
  • C
    q w ΔE
    250 J 460 J 710 J
  • D
    q w ΔE
    -250 J 460 J 210 J
Solution:
1820 Upvotes Verified Answer
The correct answer is:
q w ΔE
250 J - 460 J - 210 J
Since heat is absorbed, q=+250 J

Work done =-pV2-V1

=-50 atm×10.1 L-1.0 L

=-0.50 atm×9.1 L

=-0.50×9.1 L atm×101.0 J1 L atm=-460.0 J

Also ΔE=q+w=250 J-460 J=-210 J

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