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A gas is taken through the cycle $A \rightarrow B \rightarrow C \rightarrow A$, as shown. What is the net work done by the gas?
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Verified Answer
The correct answer is:
$1000 \mathrm{~J}$
Net work done = Area enclased in $p V$ curve, i.e., $\triangle \mathrm{ABC}$
$\begin{aligned}
& =\frac{1}{2} \times 5 \times 10^{-3} \times 4 \times 10^5 \mathrm{~J} \\
& =10^3 \mathrm{~J} \\
& =1000 \mathrm{~J}
\end{aligned}$
$\begin{aligned}
& =\frac{1}{2} \times 5 \times 10^{-3} \times 4 \times 10^5 \mathrm{~J} \\
& =10^3 \mathrm{~J} \\
& =1000 \mathrm{~J}
\end{aligned}$
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