Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A gas is undergoing an adiabatic process. At a certain stage, the volume and absolute temperature of the gas are V0, T0 and the magnitude of the slope of the V-T curve is m. molar specific heat of the gas at constant pressure is [Assume the volume of the gas is taken on the y-axis and absolute temperature of the gas taken on x-axis]
PhysicsThermodynamicsJEE Main
Options:
  • A mRT0V0
  • B mRT02V0
  • C V0+mT0RV0
  • D V0+mT0R2V0
Solution:
2297 Upvotes Verified Answer
The correct answer is: V0+mT0RV0
For adiabatic process TVγ-1= constant Differentiating with respect to T

V γ1 +T( γ1 ) V γ2 dV dt =0

      dVdT=-VTγ-1dVdTT0, V0=m

V0T0γ-1=m

γ-1=V0T0m

CV=Rγ-1=RT0mV0

CP=CV+R=1+T0mV0R

=( V 0 +m T 0 V 0 )R

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.