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A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is
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$15 \mathrm{RT}$
$U=\frac{f_{1}}{2} n_{1} R T+\frac{f_{2}}{2} n_{2} R T$
Considering translational and rotational modes, degrees of freedom $\mathrm{f}_{1}=5$ and $\mathrm{f}_{2}=3$ $\therefore \mathrm{u}=\frac{5}{2}(3 \mathrm{RT})+\frac{3}{2} \times 5 \mathrm{RT}$
$\mathrm{U}=15 \mathrm{RT}$
Considering translational and rotational modes, degrees of freedom $\mathrm{f}_{1}=5$ and $\mathrm{f}_{2}=3$ $\therefore \mathrm{u}=\frac{5}{2}(3 \mathrm{RT})+\frac{3}{2} \times 5 \mathrm{RT}$
$\mathrm{U}=15 \mathrm{RT}$
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