A gas molecule of mass M at the surface of the earth has kinetic energy equivalent to 0 ° C . If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than the radius of the earth. ( k B is Boltzmann constant)

Question

A gas molecule of mass M at the surface of the earth has kinetic energy equivalent to 0 ° C . If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than the radius of the earth. ( k B is Boltzmann constant), 273 k B 2 M g, 8 1 9 k B 2 M g, 0, 5 4 6 k B 3 M g

MARKS App · Accepted Answer

M g h = 1 2 M v rms 2 = 1 2 M 3 k T m ⇒ v rms 2 = 819 k M Now apply v 2 = u 2 − 2 g h undefined

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