Search any question & find its solution
Question:
Answered & Verified by Expert
A generator with a circular coil of 100 turns of area $2 \times 10^{-2} \mathrm{~m}^2$ is immersed in a $0.01 \mathrm{~T}$ magnetic field and rotated at a frequency of $50 \mathrm{~Hz}$. The maximum emf which is produced dwing a cycle is
Options:
Solution:
2343 Upvotes
Verified Answer
The correct answer is:
$6.28 \mathrm{~V}$
Given,
Number of turns in circular coil $=100$
Area $(A)=2 \times 10^{-2} \mathrm{~m}^2$
Magnetic field $(B)=0.01 \mathrm{~T}$
Frequency of rotation $(f)=50 \mathrm{~Hz}$
We know that,
$$
\begin{aligned}
e & =N B A \omega=N B A(2 \pi f) \\
& =100 \times 0.01 \times 2 \times 10^{-2} \times 2 \times \frac{22}{7} \times 50 \\
& =6.28 \mathrm{~V}
\end{aligned}
$$
Number of turns in circular coil $=100$
Area $(A)=2 \times 10^{-2} \mathrm{~m}^2$
Magnetic field $(B)=0.01 \mathrm{~T}$
Frequency of rotation $(f)=50 \mathrm{~Hz}$
We know that,
$$
\begin{aligned}
e & =N B A \omega=N B A(2 \pi f) \\
& =100 \times 0.01 \times 2 \times 10^{-2} \times 2 \times \frac{22}{7} \times 50 \\
& =6.28 \mathrm{~V}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.