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Question: Answered & Verified by Expert
A graph plotted between logt50 vs log concentration is a straight line. What conclusion can you draw from the given graph?



[Given: n = order of reaction]
ChemistryChemical KineticsJEE Main
Options:
  • A n=1, t 1 2 = 1 k.a
  • B n=2,t12=1a
  • C n=1, t 1 2 = 0.693 k
  • D None of the above
Solution:
2454 Upvotes Verified Answer
The correct answer is: n=1, t 1 2 = 0.693 k
t12a1-n
or t12=Za1-n
or logt12=logZ+(1-n)loga
or (y)=c+mx
Thus, slope = m = 1 - n
or 1 - n = 0
So n = 1
and for I order reaction t12=0.693k.

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