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A gun of mass $10 \mathrm{~kg}$ fires 4 bullets per second. The mass of each bullet is $20 \mathrm{~g}$ and the velocity of the bullet when it leaves the gun is $300 \mathrm{~m} \mathrm{~s}^{-1}$. The force required to hold the gun when firing is
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$24 \mathrm{~N}$
Momentum of one bullet, $p=m v$
$\begin{aligned} & =20 \times 10^{-3} \times 300=6 \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1} \\ & N=\text { number of bullet per sec }=4 \\ & \therefore \frac{d p}{d t}=\text { change of momentum per sec or force } \\ & =N(p-0)=4 \times 6=24 \mathrm{~N} \\ & \end{aligned}$
$\begin{aligned} & =20 \times 10^{-3} \times 300=6 \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1} \\ & N=\text { number of bullet per sec }=4 \\ & \therefore \frac{d p}{d t}=\text { change of momentum per sec or force } \\ & =N(p-0)=4 \times 6=24 \mathrm{~N} \\ & \end{aligned}$
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