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A hail stone of mass $42 \mathrm{~g}$ falls from a height $1.8 \mathrm{~km}$ and if its entire potential energy is converted into latent heat, the mass of the hail stone on reaching the ground is
$\left(\mathrm{g}=10 \mathrm{~ms}^{-2}, \mathrm{~L}_{\text {ice }}=3.36 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}\right)$
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$\left(\mathrm{g}=10 \mathrm{~ms}^{-2}, \mathrm{~L}_{\text {ice }}=3.36 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}\right)$
Solution:
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Verified Answer
The correct answer is:
$39.75 \mathrm{~g}$
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