Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

A hanging mass M is connected to a four times bigger mass by using a string pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2Mg force. In this situation, tension in the string is x5Mg for x=_____. Neglect mass of the string and friction of the block (bigger mass) with ice slab.
(Given g= acceleration due to gravity)

PhysicsLaws of MotionJEE MainJEE Main 2022 (28 Jun Shift 1)
Solution:
2720 Upvotes Verified Answer
The correct answer is: 6

Equation for 4M: 2Mg-T=4Ma   ...1

Equation for M: T-Mg=Ma   ...2

Adding both equation we get,

Mg=5Ma a=g5

Now, tension T=Mg+Ma=6Mg5

Therefore, x=6

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.