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Question: Answered & Verified by Expert
A heat engine absorbs heat $Q_1$ at temperature $T_1$ and heat $Q_2$ at temperature $T_2$. Work done by the engine is $J\left(Q_1+Q_2\right)$. This data
ChemistryThermodynamics (C)JEE MainJEE Main 2002
Options:
  • A
    violates $1^{\text {st }}$ law of thermodynamics
  • B
    violates $1^{\text {st }}$ law of thermodynamics if $Q_1$ is $-v e$
  • C
    violates $1^{\text {st }}$ law of thermodynamics if $Q_2$ is $-$ ve
  • D
    does not violate $1^{\text {st }}$ law of thermodynamics
Solution:
2994 Upvotes Verified Answer
The correct answer is:
violates $1^{\text {st }}$ law of thermodynamics
Some mechanical energy is always converted (lost) to other forms of energy.

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