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A hockey player is moving northward and suddenly turns westward with the same speed to avoid an opponent. The force that acts on the player is
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frictional force along sotuh-west
frictional force along sotuh-west
Consider the adjacent diagram.

The force on player is due to rate of change of momentum. The direction of force acting on player will be the same as the direction of change in momentum.
Let $O A=P_1$ i.e., Initial momentum of player northward $A B=P_2$ i.e., Final momentum of player towards west. Clearly, $O B=O A+O B$
Change in momentum
$=P_2-P_1$
$=A B-O A=A B+(-O A)$
= Clearly resultant $A R$ will be along south-west.
So, it will be also the direction of force on player.

The force on player is due to rate of change of momentum. The direction of force acting on player will be the same as the direction of change in momentum.
Let $O A=P_1$ i.e., Initial momentum of player northward $A B=P_2$ i.e., Final momentum of player towards west. Clearly, $O B=O A+O B$
Change in momentum
$=P_2-P_1$
$=A B-O A=A B+(-O A)$
= Clearly resultant $A R$ will be along south-west.
So, it will be also the direction of force on player.
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