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A hollow sphere of mass $2 \mathrm{~kg}$ is kept on a rough horizontal surface. A force of $10 \mathrm{~N}$ is applied at the centre of the sphere as shown in the figure. Find the minimum value $\mu$ so that the sphere starts pure rolling. (Take $\left.g=10 \mathrm{~m} / \mathrm{s}^2\right)$ 
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Verified Answer
The correct answer is:
$\sqrt{3} \times 0.08$
From given figure we get
$\begin{aligned}& N=F \sin \theta+m g \rightarrow(1), F \cos \theta-f=m g \rightarrow(2) \\& f R=I \alpha \rightarrow(3)\end{aligned}$
Solve above equations we can easily get
$\mu=0.08 \times \sqrt{3}$
$\begin{aligned}& N=F \sin \theta+m g \rightarrow(1), F \cos \theta-f=m g \rightarrow(2) \\& f R=I \alpha \rightarrow(3)\end{aligned}$
Solve above equations we can easily get
$\mu=0.08 \times \sqrt{3}$
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