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A horizontal overhead power line carries a current of $\mathbf{9 0} \mathrm{A}$ in east to west direction. What is the magnitude and direction of the magnetic field due to the current $1.5 \mathrm{~m}$ below the line?
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Given, $\mathrm{I}=90 \mathrm{~A}, \mathrm{a}=1.5 \mathrm{~m}, \mu_0=4 \pi \times 10^{-7}, \mathrm{~B}=$ ?
$$
B=\frac{\mu_0 I}{2 \pi \mathrm{a}}=\frac{4 \pi \times 10^{-7} \times 90}{2 \pi \times 1.5}=1.2 \times 10^{-5} \mathrm{~T}
$$
$$
B=\frac{\mu_0 I}{2 \pi \mathrm{a}}=\frac{4 \pi \times 10^{-7} \times 90}{2 \pi \times 1.5}=1.2 \times 10^{-5} \mathrm{~T}
$$
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