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Question: Answered & Verified by Expert
A horizontal rod of mass 0.01 kg and length 10 cm is placed on a frictionless plane inclined at an angle 60° with the horizontal and with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field is applied vertically downwards. If the current through the rod is 1.73 A, then the value of magnetic field induction B for which the rod remains stationary on the inclined plane is
PhysicsLaws of MotionNEET
Options:
  • A 1 T
  • B 3 T
  • C 2.5 T
  • D 4 T
Solution:
1176 Upvotes Verified Answer
The correct answer is: 1 T
Here two forces are acting on the rod simultaneously. From the hypothetical free body diagram.



mgsin60=Bilcos60o

B=mgiltan60o

=0.01×101.73×0.1×3

B=1 T

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