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A horizontal semi-circular wire of radius $\mathrm{r}$ is connected to a battery through two similar springs $\mathrm{X}$ and $\mathrm{Y}$ to an electric cell, which sends current I through it. A vertically downward uniform magnetic field B is applied on the wire, as shown in the figure. What is the force acting on each spring?
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The correct answer is:
$\mathrm{BIr}$
$F_B=i \times 2 r \times B$
$2 F=F_B$
$F=i r B$
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