A hydrogen atom in the ground state absorbs, ∆ E amount of energy. If the orbital angular momentum of the electron is increased by h 2 π ( h = Plank constant), then the magnitude of Δ E is

Question

A hydrogen atom in the ground state absorbs, ∆ E amount of energy. If the orbital angular momentum of the electron is increased by h 2 π ( h = Plank constant), then the magnitude of Δ E is, 12 . 09 eV, 12 . 75 eV, 10 . 2 eV, 13 . 6 eV

MARKS App · Accepted Answer

The electron goes to its first excited state ( n = 2 ) from the ground state ( n = 1 ) after absorbing 10 . 2 eV energy ∴ Increase in the momentum = h 2 π .

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