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A $L-C-R$ series circuit is connected to a source of alternating current. At resonance, the applied voltage and the current flowing through the circuit will have a phase difference of
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Verified Answer
The correct answer is:
$0^{\circ}$
In $L-C-R$ series circuit, phase difference $\phi$
between current and voltage is related as,
At resonance condition, $X_L=X_C$
$\therefore Z=\sqrt{R^2+\left(X_L-X_C\right)^2}=\sqrt{R^2+0}=R$
$\therefore$ from Eqs. (i), $\cos \phi=\frac{R}{R}=1$
$\Rightarrow \quad \cos \phi=\cos 0^{\circ} \Rightarrow \phi=0^{\circ}$
between current and voltage is related as,
At resonance condition, $X_L=X_C$
$\therefore Z=\sqrt{R^2+\left(X_L-X_C\right)^2}=\sqrt{R^2+0}=R$
$\therefore$ from Eqs. (i), $\cos \phi=\frac{R}{R}=1$
$\Rightarrow \quad \cos \phi=\cos 0^{\circ} \Rightarrow \phi=0^{\circ}$
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