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Question: Answered & Verified by Expert
A large box is moving on a horizontal floor with constant acceleration a=g. A particle is projected inside the box with velocity u and angle θ  with horizontal from box frame. For the given u the value of θ  for which horizontal range inside the box will be maximum is 
PhysicsMotion In Two DimensionsNEET
Options:
  • A π4
  • B π8
  • C 3π8
  • D π3
Solution:
1400 Upvotes Verified Answer
The correct answer is: π8
T= 2u sinθg

R= u2 sin2θg2u2 sin2θg

R will be maximum when dRdθ=0

2 u 2 g cos2θ 2 u 2 g .2sinθcosθ=0

2cos2θ=4sinθcosθ

cos2θ=sin2θ

2θ= π 4

θ=π8

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