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Question: Answered & Verified by Expert
A large hollow metal sphere of radius R has a small opening at the top. Small drops of mercury, each of radius r and charged to a potential V, fall into the sphere. The potential of the sphere becomes V' after N drops fall into it. Then 
PhysicsElectrostaticsJEE Main
Options:
  • A V=V for any value of N
  • B V=V for N=Rr2/3
  • C V=V for N=Rr1/3
  • D V=V for N=Rr
Solution:
1332 Upvotes Verified Answer
The correct answer is: V=V for N=Rr1/3
V=kqr

After N drop potential of hollow sphere=V





V=kNqR

V=V  kqr=kNqR

N=Rr

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