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Question: Answered & Verified by Expert

A laser beam of power 27 mW has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by

[Given permittivity of space ε09×10-12 C2 N-1 m-2, speed of light c=3×108 m s-1

PhysicsElectromagnetic WavesJEE Main
Options:
  • A 1 kV m-1
  • B 1.4 kV m-1
  • C 0.7 kV m-1
  • D 2 kV m-1
Solution:
1240 Upvotes Verified Answer
The correct answer is: 1.4 kV m-1

I=PA=12ε0E02c

E0=2Pε0CA=2×27×10-3×36π×1093×108×10×10-6

E0=1.4 kV m-1

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