Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

A lead bullet strikes a target with a velocity of 480 ms-1. After the impact, the bullet falls dead and the heat produced in the process gets equally shared between the bullet and the target. If the specific heat capacity of lead is c=0.03 cal/g/°C, then the rise in temperature of the bullet is

PhysicsThermodynamicsJEE Main
Options:
  • A 557
  • B 457
  • C 857
  • D 754
Solution:
2955 Upvotes Verified Answer
The correct answer is: 457
Q=12K.E.mcT=1212m v2J

T=v24Jc= 480×4804×4.2×(0.03×103)=457

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.