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A lift is tied with thick iron ropes having mass 'M'. The maximum acceleration of the lift is 'a' $\mathrm{m} / \mathrm{s}^{2}$ and maximum safe stress is 's' $\mathrm{N} / \mathrm{m}^{2}$. The minimum diameter of the rope is ( $\mathrm{g}=$ acceleration due to gravity $)$
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The correct answer is:
$\left[\frac{4 \mathrm{M}(\mathrm{g}+\mathrm{a})}{\pi \mathrm{s}}\right] \overline{\frac{1}{2}}$
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