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A light bulb, a capacitor and a battery are connected together as shown here, with switch $S$ initially open. When the switch $S$ is closed, which one of the following is true

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The correct answer is:
The bulb will light up for an instant when the capacitor starts charging
Initially when key is closed, the capacitor acts as short-circuit, so bulb will light up. But finally the capacitor becomes fully charged, so it will act as open circuit, so bulb will not glow.
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