A light of intensity 16 m W and energy of each photon 10 e V incident on a metal plate of work function 5 eV and area 10 - 4 m 2 then find the maximum kinetic energy of emitted electrons and the number of photoelectrons emitted per second if photon efficiency is 10 %.

Question

A light of intensity 16 m W and energy of each photon 10 e V incident on a metal plate of work function 5 eV and area 10 - 4 m 2 then find the maximum kinetic energy of emitted electrons and the number of photoelectrons emitted per second if photon efficiency is 10 %., 5 eV , 10 11, 10 eV , 10 12, 5 eV , 10 13, 10 eV , 10 14

MARKS App · Accepted Answer

Maximum K E = h C λ - ϕ = 10 - 5 = 5 eV Intensity I = N p h C λ t A ⇒ N p t = I A h C λ and the number of emitted photoelectrons per second. = N p t × 10 % = I A h C λ × 1 10 = 16 × 10 - 3 × 10 - 4 10 × 1.6 × 10 - 19 × 10 = 10 11

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