A light of wavelength 6328 Å is incident normally on a slit of width 0 . 2 mm . The angular width of the central maximum on the screen will be

Question

A light of wavelength 6328 Å is incident normally on a slit of width 0 . 2 mm . The angular width of the central maximum on the screen will be, 0 . 9 °, 0 . 18 °, 0 . 54 °, 0 . 36 °

MARKS App · Accepted Answer

a sin ⁡ θ = n λ sin ⁡ θ = n λ a = 6328 × 10 - 10 × 1 0 .2 × 10 - 3 = 3164 × 10 - 6 r a d = 0.003164 r a d ∴ Angular width = 2 θ = 2 × 0.003164 × 180 ° π = 0.36 °

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