A light ray moving in medium-I (of refractive index n 1 ) is incident on interface of two media and it is totally internally reflected at the interface. Now, refractive index n 2 of medium-II is decreased, then

Question

A light ray moving in medium-I (of refractive index n 1 ) is incident on interface of two media and it is totally internally reflected at the interface. Now, refractive index n 2 of medium-II is decreased, then, ray will move completely parallel to the interface, ray will be still totally internally reflected at interface, ray will be totally transmitted into medium-II only, if angle of incidence is increased, ray will be totally transmitted in medium-II

MARKS App · Accepted Answer

As n 2 decreases, i C = sin - 1 ⁡ n 2 n 1 also decreases. So, condition i > i C is still satisfied and there will be still total internal reflection at interface. If angle of incidence is increased, then ray will be still totally internally reflected at interface because i > i C .

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