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Question: Answered & Verified by Expert
A light rod of length, l has two masses, m1 and m2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is
PhysicsRotational MotionNEETNEET 2016 (Phase 2)
Options:
  • A m1m2m1+m2l2
  • B m1+m2m1m2l2
  • C m1+m2l2
  • D m1m2l2
Solution:
1156 Upvotes Verified Answer
The correct answer is: m1m2m1+m2l2



x1=m2lm1+m2 and x2=m1lm1+m2.

I=m1x12+m2x22=m1m2m1+m2l2.

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