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A light wave is incident normally over a slit of width $24 \times 10^{-5} \mathrm{~cm}$. The angular position of second dark fringe from the central maxima is $30^{\circ}$. What is the wavelength of light
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$6000 Å$
For second dark fringe $d \sin \theta=2 \lambda$
$\begin{aligned} & \Rightarrow \quad 24 \times 10^{-5} \times 10^{-2} \times \sin 30=2 \lambda \\ & \Rightarrow \quad \lambda=6 \times 10^{-7} \mathrm{~m}=6000 Å\end{aligned}$
$\begin{aligned} & \Rightarrow \quad 24 \times 10^{-5} \times 10^{-2} \times \sin 30=2 \lambda \\ & \Rightarrow \quad \lambda=6 \times 10^{-7} \mathrm{~m}=6000 Å\end{aligned}$
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