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A line perpendicular to the line $a x+b y+c=0$ and passes through $(a, b)$. The equation of the line is
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The correct answer is:
$b x-a y=0$
The required equation of line which passes through $(a, b)$ and gradient $\frac{b}{a}$ is, $y-b=\frac{b}{a}(x-a)$ $\Rightarrow b x-a y=0$
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