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Question: Answered & Verified by Expert
A linear object of height 10 cm is kept in front of a concave mirror of radius of curvature 15 cm, at a distance of 10 cm. The image formed is
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Options:
  • A Magnified and erect
  • B Magnified and inverted
  • C Diminished and erect
  • D Diminished and inverted
Solution:
2401 Upvotes Verified Answer
The correct answer is: Magnified and inverted
Given,

Height of object h0=10 cm

Radius of curvature R=15 cm

Distance of object u=-10 cm

We know that,

f=R2=152 cm

According to mirror formula,

1f=1u+1v

1-152=1-10+1v

  1v=-215+110

  1v=-4+330

  1v=-130

  v=-30 cm

Magnification m=hiho=-vu

=hi10=--30-10

  hi=-3

Hence, image will be magnified and inverted.  

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