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A liquid is flowing through a non-sectional tube with its axis horizontally. If two points $\mathrm{X}$ and $\mathrm{Y}$ on the axis of tube has a sectional area $2.0 \mathrm{~cm}^{3}$ and $25 \mathrm{~mm}^{2}$ respectively then find the flow velocity at $Y$ when the flow velocity at $X$ is $10 \mathrm{~m} / \mathrm{s}$.
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Verified Answer
The correct answer is:
$80 \mathrm{~m} / \mathrm{s}$
According to principle of continuity
$$
v_{y}=\frac{v_{x} A_{x}}{A_{y}}=\frac{10(m / s) \times 2\left(c m^{2}\right)}{25 \times 10^{-2}\left(c m^{2}\right)}=80 \mathrm{~m} / \mathrm{s}
$$
$$
v_{y}=\frac{v_{x} A_{x}}{A_{y}}=\frac{10(m / s) \times 2\left(c m^{2}\right)}{25 \times 10^{-2}\left(c m^{2}\right)}=80 \mathrm{~m} / \mathrm{s}
$$
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