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A logic circuit provides the output $Y$ as per the following truth table :
\begin{array}{|l|l|l|}\hlineA & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 0 \\1 & 0 & 1 \\1 & 1 & 0 \\\hline\end{array}
The expression for the output $Y$ is :
Options:
\begin{array}{|l|l|l|}\hlineA & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 0 \\1 & 0 & 1 \\1 & 1 & 0 \\\hline\end{array}
The expression for the output $Y$ is :
Solution:
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Verified Answer
The correct answer is:
$\bar{B}$
\begin{array}{|l|l|l|}\hlineA & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 0 \\1 & 0 & 1 \\1 & 1 & 0 \\\hline\end{array}
According to given truth table, output is independent on value of $A$
$\therefore$ Output $Y=\bar{B}$
According to given truth table, output is independent on value of $A$
$\therefore$ Output $Y=\bar{B}$
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